Optimal. Leaf size=196 \[ \frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{960 c^3 f (c-c \sin (e+f x))^{7/2}}+\frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{160 c^2 f (c-c \sin (e+f x))^{9/2}}+\frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{40 c f (c-c \sin (e+f x))^{11/2}}+\frac{(A+B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}} \]
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Rubi [A] time = 0.483459, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.075, Rules used = {2972, 2743, 2742} \[ \frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{960 c^3 f (c-c \sin (e+f x))^{7/2}}+\frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{160 c^2 f (c-c \sin (e+f x))^{9/2}}+\frac{(A-3 B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{40 c f (c-c \sin (e+f x))^{11/2}}+\frac{(A+B) \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}} \]
Antiderivative was successfully verified.
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Rule 2972
Rule 2743
Rule 2742
Rubi steps
\begin{align*} \int \frac{(a+a \sin (e+f x))^{5/2} (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{13/2}} \, dx &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}}+\frac{(A-3 B) \int \frac{(a+a \sin (e+f x))^{5/2}}{(c-c \sin (e+f x))^{11/2}} \, dx}{4 c}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{40 c f (c-c \sin (e+f x))^{11/2}}+\frac{(A-3 B) \int \frac{(a+a \sin (e+f x))^{5/2}}{(c-c \sin (e+f x))^{9/2}} \, dx}{20 c^2}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{40 c f (c-c \sin (e+f x))^{11/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{160 c^2 f (c-c \sin (e+f x))^{9/2}}+\frac{(A-3 B) \int \frac{(a+a \sin (e+f x))^{5/2}}{(c-c \sin (e+f x))^{7/2}} \, dx}{160 c^3}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{12 f (c-c \sin (e+f x))^{13/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{40 c f (c-c \sin (e+f x))^{11/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{160 c^2 f (c-c \sin (e+f x))^{9/2}}+\frac{(A-3 B) \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{960 c^3 f (c-c \sin (e+f x))^{7/2}}\\ \end{align*}
Mathematica [A] time = 5.74742, size = 144, normalized size = 0.73 \[ \frac{a^2 \sqrt{a (\sin (e+f x)+1)} \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right ) (6 (6 A+7 B) \sin (e+f x)-15 (A+B) \cos (2 (e+f x))+29 A-10 B \sin (3 (e+f x))+13 B)}{120 c^6 f (\sin (e+f x)-1)^6 \sqrt{c-c \sin (e+f x)} \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.332, size = 423, normalized size = 2.2 \begin{align*}{\frac{ \left ( -444\,A+52\,B+444\,A\sin \left ( fx+e \right ) +545\,A \left ( \cos \left ( fx+e \right ) \right ) ^{2}+49\,A \left ( \cos \left ( fx+e \right ) \right ) ^{4}\sin \left ( fx+e \right ) -343\,A \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) -7\,A \left ( \cos \left ( fx+e \right ) \right ) ^{5}\sin \left ( fx+e \right ) -7\,B\sin \left ( fx+e \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{4}+119\,A \left ( \cos \left ( fx+e \right ) \right ) ^{3}\sin \left ( fx+e \right ) +29\,B \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) +242\,A\cos \left ( fx+e \right ) -17\,B \left ( \cos \left ( fx+e \right ) \right ) ^{3}\sin \left ( fx+e \right ) +B \left ( \cos \left ( fx+e \right ) \right ) ^{5}\sin \left ( fx+e \right ) -224\,A \left ( \cos \left ( fx+e \right ) \right ) ^{3}+12\,B \left ( \cos \left ( fx+e \right ) \right ) ^{3}-6\,B\cos \left ( fx+e \right ) +7\,A \left ( \cos \left ( fx+e \right ) \right ) ^{6}-B \left ( \cos \left ( fx+e \right ) \right ) ^{6}+46\,B\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) -202\,A\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) +42\,A \left ( \cos \left ( fx+e \right ) \right ) ^{5}-6\,B \left ( \cos \left ( fx+e \right ) \right ) ^{5}-168\,A \left ( \cos \left ( fx+e \right ) \right ) ^{4}+24\,B \left ( \cos \left ( fx+e \right ) \right ) ^{4}-75\,B \left ( \cos \left ( fx+e \right ) \right ) ^{2}-52\,B\sin \left ( fx+e \right ) \right ) \sin \left ( fx+e \right ) }{60\,f \left ( \left ( \cos \left ( fx+e \right ) \right ) ^{3}- \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) -3\, \left ( \cos \left ( fx+e \right ) \right ) ^{2}-2\,\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) -2\,\cos \left ( fx+e \right ) +4\,\sin \left ( fx+e \right ) +4 \right ) } \left ( a \left ( 1+\sin \left ( fx+e \right ) \right ) \right ) ^{{\frac{5}{2}}} \left ( -c \left ( -1+\sin \left ( fx+e \right ) \right ) \right ) ^{-{\frac{13}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.56969, size = 490, normalized size = 2.5 \begin{align*} \frac{{\left (15 \,{\left (A + B\right )} a^{2} \cos \left (f x + e\right )^{2} - 2 \,{\left (11 \, A + 7 \, B\right )} a^{2} + 2 \,{\left (10 \, B a^{2} \cos \left (f x + e\right )^{2} -{\left (9 \, A + 13 \, B\right )} a^{2}\right )} \sin \left (f x + e\right )\right )} \sqrt{a \sin \left (f x + e\right ) + a} \sqrt{-c \sin \left (f x + e\right ) + c}}{60 \,{\left (c^{7} f \cos \left (f x + e\right )^{7} - 18 \, c^{7} f \cos \left (f x + e\right )^{5} + 48 \, c^{7} f \cos \left (f x + e\right )^{3} - 32 \, c^{7} f \cos \left (f x + e\right ) + 2 \,{\left (3 \, c^{7} f \cos \left (f x + e\right )^{5} - 16 \, c^{7} f \cos \left (f x + e\right )^{3} + 16 \, c^{7} f \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sin \left (f x + e\right ) + A\right )}{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{5}{2}}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac{13}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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